Advanced Physics for Brachytherapy 2018

3. Higher order of scatter

I have to repeat the method 2 times:

• The second step is approximate in that I do not know the orientation of H msc I can assume it is isotropic or align it with h 1sc

→ S

→ CC with h

→ D

D

prim

1sc

1sc

1sc

→ S

→ CC with H

→ D

D

1sc

2sc

msc

msc

Calculation time increases to (M 1sc +M msc )N 3

•

Required M

is < M

since the

•

msc

1sc

gradient of D

is considerably less than that of D prim

1sc