BCRB 2018
EQD2 vs BED
EQD2 = D d + α / β 2 + α / β ⎛ ⎝⎜ ⎞ ⎠⎟
BED = EQD0 = D d + α / β 0 + α / β ⎛ ⎝⎜ ⎞
⎠⎟ = D 1 + d ⎛ ⎝⎜
⎞ ⎠⎟
α / β
Michael Joiner
Basic Clinical Radiobiology 2018
Page 4 of 12
Made with FlippingBook - Online catalogs
EQD2 vs BED
EQD2 = D d + α / β 2 + α / β ⎛ ⎝⎜ ⎞ ⎠⎟
BED = EQD0 = D d + α / β 0 + α / β ⎛ ⎝⎜ ⎞
⎠⎟ = D 1 + d ⎛ ⎝⎜
⎞ ⎠⎟
α / β
Michael Joiner
Basic Clinical Radiobiology 2018
Page 4 of 12
Made with FlippingBook - Online catalogs