Basic Clinical Radiobiology 2017

Prostate cancer case

• Question 5: Which dose may be delivered to the rectum in the 4 remaining fractions to not exceed Rectum D max ? (α/β is assumed to be 3 for late toxicity) • Given: Fraction 1(Rectum) Tolerance (Rectum) - D max = 9,5 Gy - D max = 42 Gy - n = 1 - n = 5 - d = 9,5 Gy - d = 8,4 Gy